The men's football tournament at the 2019 Pan American Games was held in Lima from 29 July to 10 August 2019.
A total of eight men's teams qualified to compete at the games, four CONMEBOL teams and four CONCACAF teams.[1] For CONMEBOL, the best three teams at the 2019 South American U-20 Championship qualified, while Peru automatically qualified as hosts. For CONCACAF, the best team from each of the three zones (North American, Central American and Caribbean) at the 2018 CONCACAF U-20 Championship qualified, however, United States (best North American team) declined to participate and were replaced by Mexico. Honduras also qualified by decision of CONCACAF.[2]
The draw of the tournament was held on 12 April 2019, 12:00 PET (UTC−5), at the Peruvian Football Federation headquarters in Lima, Peru.[3][4] The eight teams were drawn into two groups of four and each group was conformed by two CONCACAF teams and two CONMEBOL teams. The hosts Peru were seeded into group B and assigned to position 4 in their group, while the remaining seven teams were placed into two pots according to the confederation which they belong.
The CONCACAF teams were drawn first and assigned to positions 1 and 2 in groups A and B. Then, the CONMEBOL teams were drawn and the first two teams occupied positions 3 and 4 in group A while the third team occupied the position 3 in group B. The draw resulted in the following groups:[5]
The draw was led by Hugo Figueredo, competition director of CONMEBOL, and had the help of Miriam Tristan and Cindy Novoa members of the Peru women's national football team
Players must be born on or after 1 January 1997, three overage players are allowed.
The referees and assistant referees were:[6]
All times are local, PET (UTC−5).[7]
If necessary, extra time and penalty shoot-out are used to decide the winner.
There were 50 goals scored in 18 matches, for an average of 2.78 goals per match.
6 goals
4 goals
3 goals
2 goals
1 goal
1 own goal
Source: Lima 2019